But, if you increase the diameter of the pipe, and the pump is only rated at x psi at x diameter, wouldn't increasing the diameter simply decrease the pressure? ie: you can move lots of water, but not very quickly due to low pressure....(not arguing, just asking....)
You keep confusing pressure with flow.
Pressure = unit weight x h (height)
Pressure (water) = 1000 kg/m3 x 9.81 m/s2 x height m
=9810 N/m2 x h(m)
= 9.81 KN/m3 x h(m)
If you had a vertical pipe, 2 metres tall, filled with water, the pressure would be 9.81 KN/m3 x 2m
= 18.6 KN/m2
= 18.6 KPa
in imperial....
P = gamma h
= 62.4 lbs/ft3 x h (ft)
If you had a pipe 5 feet vertical, the pressure would be
62.4 lbs/ft3 x 5 ft
310 lbs/ft2
= 2.15 lbs/in2 (psi)
Pressure is constant in a pipe, whether it's 1/8" in diameter, or 10 feet in diameter.
The pressure rating of a pipe simply means how much pressure it is rated to withstand and the diameter is the diameter.
Flow Q = VA
V= velocity
A = Area
The term "low water pressure" is a misnomer. It's not low water pressure, it's low water flow.
The pressure in a system is constant (well, except for friction losses I suppose, but let's ignore that for the moment as that then becomes multivariable calculus....)
If pressure is constant, velocity is constant, the only variable is cross-sectional area of the pipe.
Think of it this way.....assume that water pressure is constant in the city's network at 60 psi.
Now, I give you a garden hose with a diameter of a half inch. Therefore, the cross sectional area = pi r2 = .25 x .25 x 3.14159 = .2 inches squared.
You pretty much can visualize how much water is going to come out of that hose.
Now imagine I told you to hold a watermain that is 12 inches in diametre while I turn on the water.
You'd get the fuck out of there in a hurry.
Yet the pressure is the same in both pipes.
It's just the bigger one can deliver a much greater quantity of water (or flow) because of its larger diameter.