Lotto 649

swouwee

Active member
Aug 13, 2005
291
163
43
Doesnt it make you wonder where all this money goes to....Feb 14 ticket sales was $33,478,860.00..total payout was $6,044,809.50...Feb 18 ticket sales was $46,826,498.00...total payout was $8,693,291.10...thats a total of $65,567,258.00 profit.Should'nt our health care.roads,schools,etc etc etc be well maintained with that kind of money.
 
Ya think!?
 
Aww don't get me started on the lotteries! They're all fixed and crooked.
One day the truth will come out.
 
Personally I love them.

Voluntary taxation and yes I do play.
 
toughb said:
Personally I love them.

Voluntary taxation.

I call it stupid tax...

Odds of getting the right numbers:

There are 49 #'s and 6 choices... so:

49 x 48 x 47 x 46 x 45 x 44= 10,068,347,520 : 1

(no, I don't play...)

I work with a guy that buys at least $30 a week... double when the jackpots get bigger... so he spends about $1800 - $2000/ year. That's alot of lap dances! LOL! :D
 
Cycleguy007 said:
I call it stupid tax...

Odds of getting the right numbers:

There are 49 #'s and 6 choices... so:

49 x 48 x 47 x 46 x 45 x 44= 10,068,347,520 : 1

(no, I don't play...)

I work with a guy that buys at least $30 a week... double when the jackpots get bigger... so he spends about $1800 - $2000/ year. That's alot of lap dances! LOL!

Sorry to be pedantic, but your math is off (slightly...well, off by about 4 orders of magnitude). It would be correct if the numbers had to be in a specific order, but they do not.

So, you may redeem yourself by applying the correction to get the probability for a non-ordered set of 6 numbers from 49 :)

Prove that you're not just some jock!!!
 
Lottery games are random (by law), so they are obviously a good
example of random probability. Let's take an example lottery
where you must pick 6 unique numbers in any order from 1 to 49.
Remember that the first step is to count the number of possible
combinations: there are 49 choices for the first number. You
can't pick the same number twice, so there are only 48 choices
for the second number, 47 choices for the third number, and so on.
Therefore, the total number of possible combinations is
49*48*47*46*45*44 (or 49!/43! on your calculator), which
equals approximately 10.07 billion. However, you can pick
the 6 numbers in any order, and there are 720 possible ways
to arrange 6 numbers (6*5*4*3*2*1, or 6! on your calculator; now
you know what that x! button is for). Therefore, the overall
probability is 10.07 billion divided by 720 orders, or 13.98
million (probability math short-hand for this whole process is
"49 choose 6", or 49C6). Therefore, the odds of any given
set of numbers coming up in this type of lottery are roughly 1
in 14 million. And if you play two sets of numbers in
the same lottery draw, then your odds of winning are roughly 2 in
14 million, or 1 in 7 million.
 
Oops... had some biz to take care of... back now.

A1P took care of it for me... Thanks dude...

I also found this:

http://www.worsleyschool.net/science/files/lotto/winning649.html

The most interesting thing is this line: [FONT=arial, times new roman][SIZE=+1]This means that 98% of the time, you won't win anything!
[/SIZE][/FONT]
Which is, in and of itself the reason I don't play lotteries at all...
 
a 1 player said:
Lottery games are random (by law), so they are obviously a good
example of random probability. Let's take an example lottery
where you must pick 6 unique numbers in any order from 1 to 49.
Remember that the first step is to count the number of possible
combinations: there are 49 choices for the first number. You
can't pick the same number twice, so there are only 48 choices
for the second number, 47 choices for the third number, and so on.
Therefore, the total number of possible combinations is
49*48*47*46*45*44 (or 49!/43! on your calculator), which
equals approximately 10.07 billion. However, you can pick
the 6 numbers in any order, and there are 720 possible ways
to arrange 6 numbers (6*5*4*3*2*1, or 6! on your calculator; now
you know what that x! button is for). Therefore, the overall
probability is 10.07 billion divided by 720 orders, or 13.98
million (probability math short-hand for this whole process is
"49 choose 6", or 49C6). Therefore, the odds of any given
set of numbers coming up in this type of lottery are roughly 1
in 14 million. And if you play two sets of numbers in
the same lottery draw, then your odds of winning are roughly 2 in
14 million, or 1 in 7 million.
So, if I have 28 million dollars, I could buy 14 million tickets sequentially and be guaranteed to win the 48 million dollars. Anyone want to chip in? Let's pray that there are not multiple winners.
 
a 1 player said:
Lottery games are random (by law), so they are obviously a good
example of random probability. Let's take an example lottery
where you must pick 6 unique numbers in any order from 1 to 49.
Remember that the first step is to count the number of possible
combinations: there are 49 choices for the first number. You
can't pick the same number twice, so there are only 48 choices
for the second number, 47 choices for the third number, and so on.
Therefore, the total number of possible combinations is
49*48*47*46*45*44 (or 49!/43! on your calculator), which
equals approximately 10.07 billion. However, you can pick
the 6 numbers in any order, and there are 720 possible ways
to arrange 6 numbers (6*5*4*3*2*1, or 6! on your calculator; now
you know what that x! button is for). Therefore, the overall
probability is 10.07 billion divided by 720 orders, or 13.98
million (probability math short-hand for this whole process is
"49 choose 6", or 49C6). Therefore, the odds of any given
set of numbers coming up in this type of lottery are roughly 1
in 14 million. And if you play two sets of numbers in
the same lottery draw, then your odds of winning are roughly 2 in
14 million, or 1 in 7 million.

You're back on the drugs, aren't ya!
 
Before the draw, my lottery ticket cost $2 and was worth a 1 in 14 million chance to win.

Today, it's worth a zero in 14 million chance to win - a decline of only 1/14 millionth of its value yesterday.

I'll sell it to you for half price - putting the relative value of the ticket up astronomically! :)
 
a 1 player said:
There are days I wish I was brother. Just remembering college statistics, and using a little Google search.
***

Hell and I thought you were smart...:)
Very disillusioning
 
Rono said:
So, if I have 28 million dollars, I could buy 14 million tickets sequentially and be guaranteed to win the 48 million dollars. Anyone want to chip in? Let's pray that there are not multiple winners.

I think I remember someone tried to get an investment group together to do that and the OLGC wouldn't let them.
 
Math aside, I view it as buying a fantasy. You buy your ticket today (Thursday) and dream about winning until the reality hits on Saturday night. But you get about 48 hours of imagining what it would be like to win.
 
I saw a TV show (documentary) a while back where a guy in the US somehow got the money from the bank to cover the cost of buying every permatation of numbers for a state lottery. He and his colleagues were only allowed to buy from regular outlets and I think they managed to buy 75% of the possible numbers. They did win, don't know what the profit margin was.