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Another Logic Question

Titalian

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Nov 27, 2012
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There is no doubt they would all but up there hands.
 

IM469

Well-known member
Jul 5, 2012
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I think the candidate with the biggest tits will get the job. This is just a ruse to get the candidate you want. Even if a candidate you don't want guesses correctly, you take the hat off quickly and tell him he failed.


Like she's ever going to guess wrong !
 

GPIDEAL

Prolific User
Jun 27, 2010
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Higher the one with the nicest tits!!!

Oh wait, it's not the 60's any more.
Years ago, there was this adult video store on Dundas St. in Etobicoke. He had a sign advertising a position for a female store clerk and specified, "B Cup" preferred. That's probably illegal to do, but he was a sketchy type of guy, lol. (True story).
 

Titalian

No Regrets
Nov 27, 2012
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I think the candidate with the biggest tits will get the job. This is just a ruse to get the candidate you want. Even if a candidate you don't want guesses correctly, you take the hat off quickly and tell him he failed.


Like she's ever going to guess wrong !
Man did you see the legggggs on her. Holy fuk!!
 

buttercup

Active member
Feb 28, 2005
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The answer in the back of the book is:
"All three know there are either two or three bowlers (if there was only one, only two hands would have gone up). Therefore there is either one top hat or none. If any one could see a top hat he would know he was wearing a bowler. Since no one has said anything they must all be wearing bowlers."
A beautiful answer -- simple; concise. But Wrong.

The first point in the "answer" is:
All three know there are either two or three Bowlers..
No probs with this first point. The three candidates can all deduce that the choice is between BBB and BBT only.

However, we cannot assume that they will all 'get it' at the same time, And we cannot assume that any of them will get it immediately. (Few Loungers twigged that point right off, although we all accept it now we have thought it through.)

So there sure is a problem with the second point of the supposed answer: If any one could see a top hat he would know he was wearing a bowler. Since no one has said anything, they must all be wearing bowlers.

There is another perfectly simple, and highly likely, explanation why nobody has said anything: the fact that they haven't said anything could indicate merely that they haven't figured it out yet. The reason the others didn't say anything might very well be simply that they are slow on the uptake.

There is nothing in the question to indicate that the candidates must all have the same level of expertise in logical thinking, and they must all reach the same conclusion quickly. In fact, the set task is supposed to be a test of logic. And here's the dude with the supposed best logic, and yet his proof depends upon the other two being the logical equals of himself and him relying on their reactions as such -- in a test to find out who is the best logician. I should cocoa.

Miss Croft, the chap who knew the answer had left the building.
 

oldjones

CanBarelyRe Member
Aug 18, 2001
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A beautiful answer -- simple; concise. But Wrong.

The first point in the "answer" is:
All three know there are either two or three Bowlers..
No probs with this first point. The three candidates can all deduce that the choice is between BBB and BBT only.

However, we cannot assume that they will all 'get it' at the same time, And we cannot assume that any of them will get it immediately. (Few Loungers twigged that point right off, although we all accept it now we have thought it through.)

So there sure is a problem with the second point of the supposed answer: If any one could see a top hat he would know he was wearing a bowler. Since no one has said anything, they must all be wearing bowlers.

There is another perfectly simple, and highly likely, explanation why nobody has said anything: the fact that they haven't said anything could indicate merely that they haven't figured it out yet. The reason the others didn't say anything might very well be simply that they are slow on the uptake.

There is nothing in the question to indicate that the candidates must all have the same level of expertise in logical thinking, and they must all reach the same conclusion quickly. In fact, the set task is supposed to be a test of logic. And here's the dude with the supposed best logic, and yet his proof depends upon the other two being the logical equals of himself and him relying on their reactions as such -- in a test to find out who is the best logician. I should cocoa.

Miss Croft, the chap who knew the answer had left the building.
I quite agree, the Back of the Book answer is elegant but wrong. It completely ignores the Ontarians With Disabilities Act by simply assuming all three had hands, and were not visually impaired, and not struggling with an attention-deficit.

That stuff may be fine in the Entirely Abled World of Logic, but real people don't work that way.
 

MissCroft

Sweetie Pie
Feb 23, 2004
7,111
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Toronto
I saw a guy on the street yesterday wearing jeans, a t-shirt and a top hat. Not joking - he was either crazy or he read this thread.
 

DigitallyYours

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Oct 31, 2010
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Anyone up for a math puzzle?

The Puzzle:

ABCD x E
ABCD × E = DCBA

(Replace letters with digits and have the sum be true. A,B,C,D and E are all different digits.)
Solved this one through brute force and trial and error.

E cannot be 0 or 1.

E cannot be 9 because this would cause the result to be 5 digits long.
E cannot be 8 or 6 because A would have to be 1 and there is nothing you can multiply by 8 or 6 that ends in 1.
E cannot be 7 because A would have to be 1 (to prevent 5 digit DCBA) and D would have to be 3 (to make it end in 1) which doesn't work.
E cannot be 5 because A would have to be 1 (to prevent 5 digit DCBA) and there is nothing you can multiple by 5 that ends in 1.

E could be 4. If E=4, A cannot be 1 as this would result in an odd number for DCBA.

If E=4, A=2, then D=8. So we have 2BC8 x 4 = 8CB2.

It turns out that BC x 4 = CB - 3 has a solution if B = 1 and C = 7.

So, the answer is 2178 = 4 x 8712.

There might be other solutions.
 

thumper18474

Well-known member
Solved this one through brute force and trial and error.

E cannot be 0 or 1.

E cannot be 9 because this would cause the result to be 5 digits long.
E cannot be 8 or 6 because A would have to be 1 and there is nothing you can multiply by 8 or 6 that ends in 1.
E cannot be 7 because A would have to be 1 (to prevent 5 digit DCBA) and D would have to be 3 (to make it end in 1) which doesn't work.
E cannot be 5 because A would have to be 1 (to prevent 5 digit DCBA) and there is nothing you can multiple by 5 that ends in 1.

E could be 4. If E=4, A cannot be 1 as this would result in an odd number for DCBA.

If E=4, A=2, then D=8. So we have 2BC8 x 4 = 8CB2.

It turns out that BC x 4 = CB - 3 has a solution if B = 1 and C = 7.

So, the answer is 2178 = 4 x 8712.

There might be other solutions.
LOL...congrats
 

DigitallyYours

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Oct 31, 2010
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I have before me Iocaine powder. It is odorless, tasteless, dissolves instantly in liquid, and is among the more deadlier poisons known to man. I have two goblets. I will dissolve the Iocaine into one of the goblets and then randomize them.

All right, where is the poison? The battle of wits has begun. It ends when you decide and we both drink, and find out who is right and who is dead.
 

thumper18474

Well-known member
I have before me Iocaine powder. It is odorless, tasteless, dissolves instantly in liquid, and is among the more deadlier poisons known to man. I have two goblets. I will dissolve the Iocaine into one of the goblets and then randomize them.

All right, where is the poison? The battle of wits has begun. It ends when you decide and we both drink, and find out who is right and who is dead.
youre right.....I'm dead...LOL
 

thumper18474

Well-known member
Teaser #2

The 10-digit Number puzzle...

Find a 10-digit number where the first digit is how many zeros in the number, the second digit is how many 1s in the number etc. until the tenth digit which is how many 9s in the number.
 

DigitallyYours

Off TERB indefinitely
Oct 31, 2010
1,540
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The 10-digit Number puzzle...

Find a 10-digit number where the first digit is how many zeros in the number, the second digit is how many 1s in the number etc. until the tenth digit which is how many 9s in the number.
Are there other restrictions? Because it seems 9000000000 works but I think that's too easy...
 
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