How smart are you 4

The key is that Monty ALWAYS open a door that contains nothing, and he knows which door has the car. His action is therefore informative and alters the probabilities.

If you pick door A and Monty opens door B the odds are as follows:

1/3rd of the time the car is behind door A, and Monty randomly picks door B or C, 50% chance that he will pick either one. Monty is telling you nothing in this case.

2/3rds of the time the car is behind door B or C, and Monty has NO CHOICE in what door he opens, by opening B he is, 2/3rds of the time, telling you the car is behind C.

Thus in 2/3 cases you win by switching.

This is entirely counter-intuitive but it is nevertheless correct.

Just about

The same logic works if Monty does not know which door is empty

Except one third of the time he will reveal a BBBJCIMSW

In which case switching does not matter because you lose either way